Question

Hydrochloric acid reacts with lead (II) oxide to make lead (II) chloride and water. How many grams of hydrochloric acid are needed to make 215 moles of lead (II) chloride?

___HCl +____PbO----> ____PbCl2+____H2O

Answer 1

Answer:

$15677.8$ grams of HCl is required to produce  215 moles of lead (II) chloride

Explanation:

The balanced equation for this reaction is

2HCl + PbO -----> PbCl2 + H2O

2 molecule of HCl combines with one molecule of PbO to form one molecule of PbCl2 and one molecule of H2O

Molar mass of lead (ii chloride) - $278.1$ g/mol

Mass of $215$ moles of lead (II) chloride is

$215 * 278.1 = 59791.5$

Mass of two molecules of HCl $= 2* 36.46= 72.92$ grams

$278.1$ gram of PbO2 is formed by $72.92$ grams of HCL

1 gram of PbO2 is formed by $\frac{72.92}{278.1}$ grams of HCL

$59791.5$ gram of PbO2 is formed by $\frac{72.92}{278.1}* 59791.5$ grams of HCL

$15677.8$ grams of HCl is required to produce  215 moles of lead (II) chloride