Answer:
[tex]Q=1.16kJ[/tex]
Explanation:
Hello,
in this case, the required heat to increase the water by 5.53 °C is computed by using the mass, heat capacity and change in temperature during the process:
[tex]Q=mCp\Delta T[/tex]
Thus, for the given data we compute it in kJ:
[tex]Q=50g*4.186\frac{J}{g*\°C}*(5.53\°C)*\frac{1kJ}{1000J} \\\\Q=1.16kJ[/tex]
Best regards.