Answer:
[tex] \boxed{y = -1} [/tex]
Step-by-step explanation:
[tex] = > 16 = 4(y + 3) - 8y \\ \\ = > 16 =( 4 \times y) + (4 \times 3) - 8y \\ \\ = > 16 = 4y + 12 - 8y \\ \\ = > 16 = 12 - 4y \\ \\ = > 4y = 12 - 16 \\ \\ = > 4y = - 4 \\ \\ = > y = - \frac{4}{4} \\ \\ = > y = - 1[/tex]
