Use the ratio test to show that the series is convergent.
Thank you!

Step-by-step explanation:
lim(n→∞) |aₙ₊₁ / aₙ|
lim(n→∞) | (4ⁿ⁺¹ / (n+1)!) / (4ⁿ / n!) |
lim(n→∞) | (4ⁿ⁺¹ / (n+1)!) × (n! / 4ⁿ) |
lim(n→∞) | 4 / (n+1) |
0
Since the limit is less than 1, the series converges.
Answer:
The sum [tex]\displaystyle \sum^{\infty}_{n = 1} \frac{4^n}{n!}[/tex] converges absolutely.
General Formulas and Concepts:
Calculus
Limits
Series Convergence Tests
Step-by-step explanation:
Step 1: Define
Identify.
[tex]\displaystyle \sum^{\infty}_{n = 1} \frac{4^n}{n!}[/tex]
Step 2: Find Convergence
∴ since 0 is less than 1, the Ratio Test defines the sum [tex]\displaystyle \sum^{\infty}_{n = 1} \frac{4^n}{n!}[/tex]absolutely convergent.
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Learn more about the Ratio Test: https://brainly.com/question/16618162
Learn more about Taylor Series: https://brainly.com/question/23558817
Topic: AP Calculus BC (Calculus I + II)
Unit: Taylor Series