Question

A ball of mass 200 g rolls along the ground at a speed of 5.2m/s.calculate the kinetic energy of the ball. Give answer to one decimal place.
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Answer 1

Answer: 2704 J

Given :

mass = 200 g

velocity = 5.2 m/s

kinetic energy = 1/2 mv^2

= 1/2 * 200 * (5.2)^2

100 * 27.04

2704 J

Answer 2

The kinetic energy of the ball is 2.704 J and this can be determined by using the formula of the kinetic energy.

Given :

A ball of mass 200 g rolls along the ground at a speed of 5.2 m/s.

The following steps can be used in order to determine the kinetic energy of the ball:

Step 1 - The formula of the Kinetic energy can be used in order to determine the kinetic energy of the ball.

Step 2 - The formula of the kinetic energy is given below:

$\rm K.E. = \dfrac{1}{2}mv^2$

where m is the mass and v is the velocity.

Step 3 - Now, substitute the values of the known terms in the above formula.

$\rm K.E. = \dfrac{1}{2}\times 0.2\times (5.2)^2$

Step 4 - Simplify the above expression.

K.E. = 0.1 $\times$ 27.04

K.E. = 2.704 J

For more information, refer to the link given below:

https://brainly.com/question/999862