Answer:
The probability that exactly 19 of them are strikes is 0.1504
Step-by-step explanation:
The binomial probability parameters given are;
The probability that the pitcher throwing a strike, p = 0.675
The probability that the pitcher throwing a ball. q = 0.325
The binomial probability is given as follows;
[tex]p(x) = _{n}C_{x}\cdot p^{x}\cdot q^{1-x}[/tex]
Where:
x = Required probability
Therefore, the probability that the pitcher throws 19 strikes out of 29 pitches is found as follows;
The probability that exactly 19 of them are strikes is given as follows;
[tex]\binom{29}{19}(0.675)^{19}0.325^{10} = \frac{29!}{19!\times 10!}\times (0.675)^{19}\times 0.325^{10} = 0.1504[/tex]
Hence the probability that exactly 19 of them are strikes = 0.1504
