Question

*15 points please help easy question*
Find the value of x in the isosceles triangle shown below.
X=square root of 12
X=square root of 49
X=square root of 13
X=square root of 5

Answer 1

Answer:

x = $\sqrt{13}$

Step-by-step explanation:

The segment from the vertex to the base is a perpendicular bisector.

Using Pythagoras' identity on the right triangle on the left.

x² = 2² + 3² = 4 + 9 = 13 ( take the square root of both sides )

x = $\sqrt{13}$