Question

Help me out !!!
Jennifer can run 12 miles in 2 hours, and she can bike 33 miles in 3 hours.

a. What is Jennifer’s biking speed?
b. What is Jennifer's running speed?
c. Jennifer biked for 2 hours and then ran for 30 minutes. What distance did she cover?

Answer 1

Answer:

a) 11mph

b) 6mph

c) 25 miles

Step-by-step explanation:

She can run 12 miles in 2 hours.

She can bike 33 miles in 3 hours.

a) What is Jennifer's biking speed?

Divide:

$\frac{33mi}{3h}=11mph$

b) What is Jennifer's running speed?

Divide:

$\frac{12mi}{2h}=6mph$

c) Jennifer biked for 2 hours and then ran for 30 minutes. What distance did she cover?

She bikes 11 miles per hour.

2 hours would be = 11mi * 2 = 22miles

She runs 6 miles per hour.

30 minutes or 1/2 hour would be = 6mi * 1/2 = 3 miles

Add these distances.

22+3=25 miles

Answer 2

Answer:

a) 11 miles/hour.

b) 6 miles/hour.

c) 25 miles/hour.

Step-by-step explanation:

(The recipe is used: S=V.t ; V=S/T ; T=S/V.)

a and b) We use the recipe: V=S/t (speed= distance divided by time)

In part a, we have: 33/3=11 (miles)

in part b, we have: 12/2=6 (miles)

In part c:

+ In 3 hours,  can bike 33 miles => in one hour, She  bike: 33/3=11 miles => in 2 hours, she can bike 11x2=22 miles.

+ In 2hours, she can run 12 miles => In one hours, she can run: 12/2=6 miles => in 11 miles/hour.

b) 6 miles/hour.

c) 25 miles/hour.

Step-by-step explanation:

(The recipe is used: S=V.t ; V=S/T ; T=S/V.)

a and b) We use the recipe: V=S/t (speed= distance divided by time)

In part a, we have: 33/3=11 (miles)

in part b, we have: 12/2=6 (miles)

In part c:

+ In 3 hours, can bike 33 miles => in one hour, She bike: 33/3=11 miles => in 2 hours, she can bike 11x2=22 miles.

+ In 2hours, she can run 12 miles => In one hours, she can run: 12/2=6 miles => in half an hour, she can run: 6/2=3 miles.

+Finally, we add them up: 22+3=25 (miles)

(My mother language is not English, and hope you'll understand it. A good day.)