Answer:
[tex]\huge\boxed{x<-8\to x\in(-\infty;\ -8)}[/tex]
Step-by-step explanation:
[tex]-9.4>1.7x+4.2\qquad\text{subtract 4.2 from both sides}\\\\-9.4-4.2>1.7x+4.2-4.2\\\\-13.6>1.7x\qquad\text{divide both sides by 1.7}\\\\\dfrac{-13.6}{1.7}>\dfrac{1.7x}{1.7}\\\\-8>x\to\boxed{x<-8}[/tex]
