Question

A 15 m long wire is placed horizontally on the surface of a liquid and is gently pulled up with a force of 60 to keep the wire in equilibrium. What is the surface tension of the liquid?

Answer 1

Answer:

Explanation:

From the question we are told that

    The length of the wire is  $L = 15 \ m$

     The force with which its pulled up is  $F = 60 \ N$

The surface tension of the liquid  is mathematically  represented as

         $S = \frac{F}{2L}$

substituting values  

         $S = \frac{60}{2* 15}$

         $S = 2 Nm^{-1}$