Answer:
[tex]r = \sqrt{50}[/tex]
Explanation:
The exercise ask for the radius of the circular sector given its area and central angle. The radius is given by the following expression:
[tex]r = \sqrt{\frac{2\cdot A}{\theta}}[/tex]
[tex]r = \sqrt{\frac{20\pi}{\frac{2\pi}{5} }}[/tex]
[tex]r = \sqrt{\frac{100\pi}{2\pi}}[/tex]
[tex]r = \sqrt{50}[/tex]