Question

What is the molarity of 4 qof NaCl (MM=58.45) in 3,800 mL of solution?

0.018 M
0.001 M
1.052 M
0.062 M

chemistry

Answer 1

Answer:

.018 M

Explanation:

grams/MM=ans./volume(L) = M

4/58.45=ans./3.8=.018 M

Answer 2

The molarity of 4g of NaCl in 3,800 mL of solution is 0.018M.

HOW TO CALCULATE MOLARITY:

• The molarity of a solution can be calculated by dividing the number of moles by its volume. That is;

• molarity (M) = no. of moles (mol) ÷ volume (L)

• no. of moles = 4g ÷ 58.45g/mol = 0.068 mol

• Molarity = 0.068mol ÷ 3.8L

• Molarity = 0.018M

• Therefore, the molarity of 4g of NaCl in 3,800 mL of solution is 0.018M.

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