Question

Question 22 (2 points)

What is the radius and the center of the circle?

(x - 3)2 + (y + 2)2 = 16

Radius = 4, Center = (3,-2)

Radius = 4, Center = (3, 2)

Radius = 8, Center = (3,-2)

Radius = 8, Center = (3, 2)

mm

Answer 1

Answer:

Radius = 4, Center = (3,-2)

Step-by-step explanation:

The equation of a circle has the following format:

$(x - x_{0})^{2} + (y - y_{0})^{2} = r^{2}$

In which r is the radius(half the diameter) and the centre is the point $(x_{0}, y_{0})$

In this question, we have that:

$x_{0} = 3, y_{0} = -2, r^{2} = 16$

So the center is (3,-2) and the radius is $r = \sqrt{16} = 4$

So the correct answer is:

Radius = 4, Center = (3,-2)