Answer:
magnitude of force on charge 2Q = [tex]\frac{KQ^{2} }{I^{2} }[/tex]
Direction of force on charge = 61 ⁰
Explanation:
The magnitude on the force on the charge can be evaluated by finding the net force acting on the charge 2Q i.e x-component of the net force and the y-component of the net force
║F║ = [tex]\sqrt{f_{x}^{2} + f_{y}^{2} }[/tex] = after considering the forces coming from Q, 3Q and 4Q AND APPLYING COULOMBS LAW
magnitude of force acting on 2Q = [tex]\frac{KQ^{2} }{I^{2} }[/tex]
The direction of the force on charge 2Q is calculated as
tan ∅ = [tex]\frac{f_{y} }{f_{x} }[/tex] = 1.8284
therefore ∅ = [tex]tan^{-1}[/tex] 1.8284
= 61⁰
