Answer:
1. 64x² -48x +9
2. x = 8; (8, -62); (-∞, ∞); [-62, ∞)
Step-by-step explanation:
1) The area of a square is the square of the side length.
A = (8x -3)² = (8x)² +2(8x)(-3) +(-3)²
A = 64x² -48x +9 . . . . area of the sign
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2) Axis of symmetry:
x = -b/(2a) = -(-16)/(2(1))
x = 8 . . . . axis of symmetry
The vertex can be found by adding and subtracting the square of the above value:
y = x^2 -16x +64 +2 -64
y = (x -8)^2 -62
Compare this to "vertex form" with vertex (h, k):
y = (x -h)^2 +k
The vertex is (x, y) = (8, -62).
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The domain is all real numbers, as it is for any polynomial.
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The range is all numbers at and above the vertex.
The range is all numbers greater than or equal to -62.
