Question

PLZ help

Alice, Bob, and Carrie can all choose a number from 1 to 10 (inclusive)
Find the number of ways they can choose their numbers, if all three numbers are
different.

Answer 1

Answer: 720 ways

Step-by-step explanation:

We have a total of 10 numbers and 3 selections:

When Alice chooses, she has 10 possible numbers to choose.

When Bob chooses, he has 9 possible numbers to choose (because one has already ben selected)

When Carrie chooses, she has 8 possible numbers to choose (because two numbers had already been selected)

The number of combinations is equal to the product of the number of options for each selection:

C = 10*9*8 = 90*8 = 720