Question

given a polynomial and one of its factors bother main factors 9x^3 + 20x^2 - 68x - 16; (x+4)

Answer 1

Answer:

9x+2 and x-2.

Step-by-step explanation:

Given the polynomial $9x^3 + 20x^2 - 68x - 16$

If one of the factors is x+4, then to obtain the other factor, we divide the polynomial by the known factor.

$\dfrac{9x^3 + 20x^2 - 68x - 16}{x+4} =9x^2-16x-4$

Next, we factorize our result

$9x^2-16x-4=9x^2-18x+2x-4\\=9x(x-2)+2(x-2)\\=(9x+2)(x-2)$

Therefore, the other factors of the polynomial are 9x+2 and x-2.