Answer:
Option B will be the answer.
Step-by-step explanation:
From the figure attached,
ABC is a triangle having ∠C = 53°, a = 3 cm and b = 5 cm
Since area of a triangle = [tex]\frac{1}{2}(\text{Base})(\text{height})[/tex]
= [tex]\frac{1}{2}(BC)(AE)[/tex]
SinC = [tex]\frac{AE}{AC}[/tex]
Sin53° = [tex]\frac{AE}{5}[/tex]
AE = 5(sin53°)
= 3.993
Now area of triangle ABC = [tex]\frac{1}{2}(3.993)(3)[/tex]
= 5.99
≈ 6 square cm
Therefore, area of ΔABC = 6 cm²
Option B will be the answer.
