Question

What is the sum of a 58 term arithmetic sequence where the first term is six in the last term is 405

Answer 1

Answer:

11919

Step-by-step explanation:

S base n = n over 2 [ a + ℓ] is the sysbol of sum of arithmetic progression

S = sum, a = the fist term, ℓ = the last term, n = the term that you want to find

Now :

S base n = n over 2 [a+ℓ]

S base 58 = 58 over 2 [ 6+405]

= 29 ( 411)

= 11919