We're given the point to plug into the point-slope equation [tex]y-y_1=m(x-x_1);[/tex] now, all we need is the slope, which can be calculated using the two given points: [tex]m=\frac{12-2}{2-(-3)}=2.[/tex] Thus, our point-slope equation from the first given point is [tex]\boxed{y-2=2(x+3)}.[/tex]
