Question

Find the distance traveled in 15 seconds by an object moving with a velocity of v(t)=20+7cos(t) feet per second.

Answer 1

$s(t)= \int\limits^{15}_0 {v(t)} \, dt \\ =\int\limits^{15}_0 {(20+7cos(t))} \, dt \\ =[20t+7sin(t)]^{15}_0 \\ =(20(15)+7sin(15))-(20(0)+7sin(0)) \\ =300+1.812=301.812 \, feet$