Answer:
Option (3) will be the answer.
Step-by-step explanation:
Area of a triangle = [tex]\frac{1}{2}(\text{Base})\times (\text{Height})[/tex]
= [tex]\frac{1}{2}(AB)(CD)[/tex]
Since, m∠A + m∠B + m∠C = 180°
60° + 60° + m∠C = 180°
m∠C = 180° - 120°
m∠C = 60°
Therefore, ΔABC is an equilateral triangle.
AB ≅ BC ≅ AC ≅12
Sin 60° = [tex]\frac{CD}{BC}[/tex]
[tex]\frac{\sqrt{3}}{2}=\frac{CD}{12}[/tex]
CD = 6√3
Now area of ΔABC = [tex]\frac{1}{2}(6\sqrt{3})(12)[/tex]
= [tex]36\sqrt{3}[/tex]
= 62.35
≈ 62.4 square units
Therefore, Option (3) will be the answer.
