Question

Q bisects PR, PQ=3y, and PR=42. Find y and QR.

Answer 1

|PR| = |PQ| + |QR|; |PQ| = |QR| conclusion |PR| = 2|PQ|

|PQ| = 3y; |PR| = 42; |QR|=?

subtitute

42 = 2(3y)
6y = 42    |divide both sides by 6
y = 7

|QR| = 3(7) = 21

Answer 2

The value of y is 7 and QR is 21.

Given,

PR=42.

Q bisects PR.

PQ=3y.

We have to find the value of y and QR.

We have,

PR = 42.

Since Q bisects PR we have,

PQ = QR = 42/2

PQ = 21

QR = 21

Now,

We have,

PQ = 3y

21 = 3y

y = 21 / 3

y = 7.

Thus y is 7 and QR is 21.

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