Answer;
=98.98g of S8
Solution and explanation;
The equation for the reaction is;
8 SO2 + 16 H2S → 3 S8 + 16 H2O
Therefore;
Moles of SO2
(77.0 g SO2) / (64 g SO2/mol) = 1.203 moles
Moles of H2S
(77.0 g H2S) / (34 g H2S/mol) = 2.26 moles
2.26 moles of H2S would react completely with 2.26 x (3/16) = 0.424 moles SO2, but there is more SO2 present than that, which means that SO2 is in excess and H2S is the limiting reactant.
1.203 moles SO2 yields 3/8x amount that is = 0.456moles of S8
, thus
2.06moles H2S yields 3/16x amount = 0.386moles of S8
Hence
;
H2S will produce only 0.386moles of S8 that is equivalent to 98.98g of S8
