Question

What is the product?


StartFraction 4 n Over 4 n minus 4 EndFraction times StartFraction n minus 1 Over n + 1 EndFraction

Answer 1

Answer:

$\frac{n}{n+1}$

Step-by-step explanation:

Given the expression $\frac{4n}{4n-4} *\frac{n-1}{n+1}$

First we will factor out 4 from 4n-4 at the denominator to have;

$= \frac{4n}{4(n-1)} * \frac{n-1}{n+1}$

Cancelling out the n-1 from both numerator and denominator we have;

$= \frac{4n}{4(n+1)} \\= \frac{n}{n+1}$

n/n+1 gives the required product of the expression

Answer 2

Answer:

$\frac{4n}{4n-4} \frac{n-1}{n+1}$

We can take common factor of 4 for the term $\frac{4n}{4n-4}$ and we got:

$\frac{4}{4} \frac{n}{n-1} \frac{n-1}{n+1}$

Now we can cancel the n-1 in the denominator and the n-1 in the numerator and we got:

$1 \frac{n}{n+1}$

And the final answer would be:

$\frac{n}{n+1}$

Step-by-step explanation:

For this case we have the following product given:

$\frac{4n}{4n-4} \frac{n-1}{n+1}$

We can take common factor of 4 for the term $\frac{4n}{4n-4}$ and we got:

$\frac{4}{4} \frac{n}{n-1} \frac{n-1}{n+1}$

Now we can cancel the n-1 in the denominator and the n-1 in the numerator and we got:

$1 \frac{n}{n+1}$

And the final answer would be:

$\frac{n}{n+1}$