Respuesta :
Answer:
(d) 50 kg · m/s
Explanation:
Given;
initial momentum of first object, m₁u₁ = 25 kg. m/s
initial momentum of second object, m₂u₂ = 35 kg . m/s
final momentum of the first object, m₁v₁ = 10 kg. m/s
final momentum of the second object, m₂v₂ = ?
O --------------> + O-----------------> = O----------> + O---------------------->
Apply the principle of conservation of linear momentum;
m₁u₁ + m₂u₂ = m₁v₁ + m₂v₂
25 + 35 = 10 + m₂v₂
60 - 10 = m₂v₂
50 = m₂v₂
Therefore, the final momentum of the second object is 50 kg. m/s
(d) 50 kg · m/s
The change in momentum of the second object is obtained as 50 kg · m/s.
From the principle of conservation of linear momentum, the total momentum before collision must be equal to the total momentum after collision. This is because momentum is conserved.
Hence;
25 kg. m/s + 35 kg . m/s = 10 kg. m/s + x
x = 25 kg. m/s + 35 kg . m/s - 10 kg. m/s
x = 50 kg · m/s
The change in momentum of the second object is obtained as 50 kg · m/s.
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