Question

At a competition with 6 runners, medals are awarded for first, second, and

third places. Each of the 3 medals is different. How many ways are there to

award the medals?

Decide if this is a permutation or a combination, and find the number of ways

to award the medals.

O

A. Permutation; number of ways = 20

O

O

B. Combination; number of ways = 20

C. Permutation; number of ways = 120

O

D. Combination; number of ways = 120

SUBMIT

Answer 1

Answer:

C. Permutation; number of ways = 120

Step-by-step explanation:

The order in which the runners finish is important. For example, A,B,C means that A will be awarded the 1st place medal, B the 2nd and C the 3rd. B,A,C means that B is awarded the 1st place medal, A the 2nd and C the 3rd. So we use the permutations formula to solve this question. That is, this is a permutation.

Permutations formula:

The number of possible permutations of x elements from a set of n elements is given by the following formula:

$P_{(n,x)} = \frac{n!}{(n-x)!}$

In this question:

3 medals to 6 runners. So

$P_{(6,3)} = \frac{6!}{(6-3)!} = 120$

So the correct answer is:

C. Permutation; number of ways = 120