Question

Eight rooms in a house need to be painted.
Each room can be painted white or
yellow.​

Answer 1

Answer:

256

Step-by-step explanation:

This is just a simply problem using powers.

We have 8 rooms here, to be painted with white or yellow. so we have first 2 possibilities of colors.

We can paint the room, the eight room with just yellow, or just white. But we can also paint one room with white and 8 with yellow. And we vary and alter the order of this.

Regardless the order in which we paint the room, we have 8 rooms and only two possibilities to paint the rooms, so the math involved is just:

P = 2⁸ = 256

These are the total possibilities to paint the rooms with just these colors.

Answer 2

I guess that we want to get the number of different possible house paintings we can get. We will see that there are 256 different ways of painting the house.

Let's see how to get that answer:

So we know that the house has 8 rooms that must be painted, and each one of these 8 rooms can be painted in two different colors, so there are 2 options per room.

The total number of different combinations is equal to the product between the numbers of options.

Here we have 8 times the number of options 2, so the total number of different combinations is:

C = 2^8 = 256.

Concluding, there are 256 different ways of painting the house.

If you want to learn more, you can read:

https://brainly.com/question/15358976