20 g of water. specific heat of water is 4.18 J/xĀ°C. temperature changes from

25Ā° C to 20Ā° C, how much heat energy (Q) moves from the water to the

surroundings?

418 Joules

4.18 J

209 J

83 J

Respuesta :

Answer:

B or the second one

Explanation:

The amount of heat energy (Q) that moves from the water to the surroundings is 418J.

What is heat energy?

Heat energy, also called thermal energy, is the energy an object has because of the movement of its molecules, and heat can be transferred from one object to another object.

Given data;

Mass of water = 20g

Specific heat capacity of water = 4.18J/gĀ°C

Initial temperature = 25Ā°C

Final temperature = 20Ā°C

Unknown:

Amount of heat (Q) lost to the surroundings = ?

Solution:

The amount of heat lost to the surrounding is the same as the quantity of

heat needed to take down the temperature of the water.

Now, to solve this problem, use the mathematical equation below;

Q= m c (Tā‚‚ - Tā‚)Q is the amount of heat

m is the mass

c is the specific heat capacity

T is the temperature and 1 and 2 are initial and final states.

Now insert the parameters and solve;

Q = 20 x 4.18 x (20 - 25)

Q = -418J

Hence, the quantity of heat the moved from water to the surrounding is

418J.

Learn more about heat energy here:

https://brainly.com/question/25384702

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