Question

The equation ax2 + bx + c = 0 has no real solutions.
Which statement about the graph of f(x) = ax2 + bx + c could be true?

A. It could pass through the origin.

B. Its vertex could be at (-6, 0).

C. It could have a maximum at (-3,2).

D. It could have a minimum at (0,4).

Answer 1

Answer:

B

Step-by-step explanation:

Answer 2

The true statement about the graph is (b) its vertex could be at (-6, 0)

The equation of the graph is given as:

$f(x) = ax^2 + bx + c$

If the graph passes through the origin, then the equation has real roots.

Also, if the graph has a maximum at (-3,2) or minimum at (0,4), then the graph crosses the x-axis at two different points.

However, if the vertex of the graph is (-6,0), then the equation has no real solution

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