Respuesta :
Answer:
THE NEW PRESSURE WHEN THE GAS IS RELEASED INTO A 10 L REACTION VESSEL AND AT 33.6 °C TEMPERATURE IS 2.18 atm.
Explanation:
The general gas equation will be used to calculate the new pressure.
P1V1 /T1 = P2 V2 / T2
P1 = 4.20 atm
V1 = 5 L = 5 dm3
T1 = 22°C = 22 + 273 K = 295 K
V2 = 10 L = 10 dm3
T2 = 33.6 °C = 33.6 + 273 K = 306.6 K
P2 =?
Rearranging the formula and making P2 the subject of the equation, we have;
P2 = P1V1 T2 / T1 V2
P2 = 4.2 * 5 * 306.6 / 295 * 10
P2 = 6438.6 / 2950
P2 = 2.18 atm.
So therefore, the pressure inside the reaction vessel when the gas is released into a 10 L reaction vessel and at a temperature of 33.6 °C is 2.18 atm.
Answer:
The pressure inside the reaction vessel is 2.18 atm
Explanation:
Step 1: Data given
The temperature = 22.0 °C = 295.15 K
Pressure = 4.20 atm
Volume = 5.0 L
Volume increased to 10.0 L
Temperature increased to 33.6 °C = 306.75K
Step 2: Calculate the new pressure
P1 * V1 / T1 = P2*V2 / T2
⇒with P1 = the initial pressure = 4.20 atm
⇒with V1 = the initial volume = 5.0 L
⇒with T1 = the initial temperature = 295.15 K
⇒with P2 = the new pressure = TO BE DETERMINED
⇒with V2 = the increased volume = 10.0L
⇒with T2 = the increased temperature = 306.75 K
(4.20 atm * 5.0 L) / 295.15 K = ( P2 * 10.0 L ) / 306.75 K
P2 = (4.20 * 5.0 L * 306.75 K) / (295.15 K * 10.0 L)
P2 = 2.18 atm
The pressure inside the reaction vessel is 2.18 atm
