Question

What is an equation of the line that passes through the point (2, -3) and is perpendicular to the line 2x+5y =10 ANSWRS PLS

Answer 1

Answer:

y + 3 = (5/2)(x - 2)

Step-by-step explanation:

Take a look at the given line:  2x + 5y = 10.  Solving this for y, we get, first,

5y = -2x + 10, or

y = (-2/5)x + 2

Any line perpendicular to this one has a slope which is the negative reciprocal of -2/5.  That new slope would be 5/2.

Then the desired new line is   y + 3 = (5/2)(x - 2)