Answer:
(a) Ff = 3.95N
(b) Ff = 5N
Explanation:
(a) To find the friction force you use the second Newton law:
[tex]F=ma[/tex]
But you take into account the applied force and the opposite friction force:
[tex]F_a-F_f=ma[/tex]
you do Ff the subject of the formula and replace the values of the parameters:
[tex]F_f=F_a-ma=5N-(0.700kg)(1.5m/s^2)\\\\F_f=3.95N[/tex]
(b) In the case of a motion with constant velocity you have that there is no acceleration. Hence:
[tex]F_a-F_f=0\\\\F_f=F_a\\\\F_f=5N[/tex]