Question

A 200 kg boulder is 1000 m above the ground (c) The


boulder begins to fall. What is the its potential energy when it is 500-m


above the ground? Where did the lost potential energy go? *

Answer 1

Answer:

981,000J

Explanation:

Potential energy at 500m:

the formula for potencial energy is:

$V=mgh$

where V is the potential energy, m is the mass of the object, and h is the heigh, in this case:

mass: $m=200kg$

and h is the height, in this case: $h=500m$

g is the gravitational acceleration: $g=9.81m/s^2$

we substitute all of this values and we find the potential energy:

$V=(200kg)(9.81m/s^2)(500m)\\V=981,000J$

The potential energy is due to the height at which the object is, so as it falls it loses potential energy which is converted into kinetic energy which is the energy due to the movement of the object.

Thus the potential energy goes to convert into kinetic energy.

Answer 2

The potential energy of the boulder at the given height is required.

The potential energy of the boulder at 500 m is 981000 J.

The potential energy of the boulder at 1000 m is larger than at 500 m.

This is because the as the object is moving down the potential energy gets converted to kinetic energy.

m = Mass of object = 200 kg

h = Height = 500 m

g = Acceleration due to gravity = $9.81\ \text{m/s}^2$

Potential energy at 500 m is

$U=mgh\\\Rightarrow U=200\times 500\times 9.81\\\Rightarrow U=981000\ \text{J}$

The potential energy of the boulder at 1000 m is larger than at 500 m.

This is because the as the object is moving down the potential energy gets converted to kinetic energy.

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