Question

Given the following reaction:
2 KCIO3
-->2 KCl + 302
How many moles of KCl will be produced from 89.0 g of KCIO,?​

Answer 1

Answer:

.72 mols of KCl

Explanation:

Read the explanation while looking at the picture.

We start with 89g because it's what they give us:

89g of KCIO3 will cancel out with 123g of KCIO3 (molar mass)

~Grams of KCIO3 are canceled out.~  

That 123g of KCIO3 is the same as 1 mol of KCIO3  

Then we use mole to mole ratio:  

1 mol of KCIO3 equals 2 mols of KCIO3 -- 2 moles from the equation  

The 2 mols of KCIO3 is equal to 2 mols of KCl (from equation)  

Multiply the numbers on top. Multiply the numbers on the bottom. Then divide. You get:

$.7235772358$

This sounds confusing. But the picture below is the format.

The SAME COLOR are the ones that cancel out.