Respuesta :
We have been given that a circle is centered at D(-1,3). The point G(-10,1) is on the circle. We are asked to write the equation of circle.
We know that standard equation of a circle is [tex](x-h)^2+(y-k)^2=r^2[/tex], with center at point (h,k) and radius r.
First of all we will find radius of circle using distance formula.
[tex]r=\sqrt{(-10+1)^2+(1-3)^2}[/tex]
[tex]r=\sqrt{(-9)^2+(-2)^2}[/tex]
[tex]r=\sqrt{81+4}[/tex]
[tex]r=\sqrt{85}[/tex]
Now we will substitute coordinates of center and radius in equation of circle.
[tex](x-(-1))^2+(y-3)^2=\left(\sqrt{85}\right )^2[/tex]
[tex](x+1)^2+(y-3)^2=85[/tex]
Therefore, the equation of circle would be [tex](x+1)^2+(y-3)^2=85[/tex].
Answer:
on the circle.
Step-by-step explanation:
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