Question

Which shows how to find the value of this expression when x = negative 2 and y = 5?StartFraction 3 squared (negative 2) Superscript 6 Baseline Over 5 Superscript 4 EndFraction

StartFraction 3 (negative 2) Superscript 6 Baseline Over 5 Superscript 4 EndFraction

StartFraction 3 squared (5 Superscript 6 Baseline) Over (negative 2) Superscript negative 4 Baseline EndFraction

StartFraction 3 Over (2) Superscript 6 Baseline 5 Superscript 4 Baseline EndFraction

Answer 1

Answer:

StartFraction 3 (negative 2) Superscript 6 Baseline Over 5 Superscript 4 EndFraction

Step-by-step explanation:

The given values are $x=-2$ and $y=5$.

The given expression is

$(3x^{3} y^{-2} )^{2}$

First, we need to multiply exponents

$(3x^{3} y^{-2} )^{2}=3x^{6}y^{-4}$

Second, we move the negative exponent to the denominator side

$3x^{6}y^{-4}=\frac{3x^{6} }{y^{4} }$

If we replace each value, we have

$\frac{3x^{6} }{y^{4} }=\frac{3(-2)^{6} }{(5)^{4} }$

The statement that describes this expression is C.

Answer 2

Answer:

C

Step-by-step explanation: