Question

What are the solutions of this quadratic equation?

Answer 1

Answer:

B

Step-by-step explanation:

$2x^2+16x-8=0$

$x=\dfrac{-16\pm \sqrt{256+64}}{4}=\dfrac{-16\pm 8\sqrt{5}}{4}=-4\pm 2\sqrt{5}$, or answer choice B. Hope this helps!

Answer 2

Answer:

B

Step-by-step explanation:

2x^2 + 16x - 8 = 0 -->

x^2 + 8x - 4 = 0-->

(-b +/- sqrt(b^2 - 4ac))/2 -->

(-8 +/- sqrt(64 - (-4 * 4)))/2 -->

(-8 +/- sqrt(80))/2 -->

(-8 +/- 4sqrt5)/2 -->

-4 +/- 2sqrt5 (B)