Question

A longitudinal wave is observed to be moving along a slinky. Adjacent crests are 2.4 m apart. Exactly 6 crests are observed to move past a given point in 9.1 s. Determine the wavelength, frequency, and speed of this wave.

Answer 1

Answer:

The wavelength is 2.4 m (the distance between crests). The frequency is 0.66

Hz (6 crests/sec / 9.1 s). The speed of the wave is 0.66 * 2.4m = 1.58 m/s.

Explanation:

Answer 2

The wavelength, frequency and speed of the given wave is required.

The wavelength of the wave is 2.4 m

The frequency of the wave is 0.659 Hz.

The speed of the wave is 1.582 m/s.

The distance between adjacent crest is 2.4 m.

This is the wavelength of the wave.

$6\ \text{crest}=9.1\ \text{s}$

$1\ \text{s}=\dfrac{6}{9.1}=0.659\ \text{Hz}$

The velocity of the wave is the product of wavelength and frequency

$2.4\times \dfrac{6}{9.1}=1.582\ \text{m/s}$

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