Answer:
Hello There. I think the Correct answer is (4y+1)(y+6)
Step-by-step explanation:
Well I can't grid it for you, you didn't get give enough detail, however I can do the factoring.
Step-by-step explanation:
Given equation [tex]4y^{2} + 25y + 6[/tex][tex]4y^{2} + 25y + 6[/tex]
We have to write the given equation in factors form and then represent the factors on grid.
Consider the given equation [tex]4y^{2} + 24y + y + 6[/tex]
25y can be written as 24y + y , we get
⇒ [tex]4y^{2} + 24y + y + 6[/tex]
Taking 4y common from first two term and 1 common from last two term, we get,
⇒ [tex]4y(y + 6) + 1 (y + 6)[/tex]
⇒ [tex](4y + 1) (y + 6)[/tex]
Thus, factored form of given equation [tex]4y^{2} + 25y + 6 (4y + 1) (y + 6)[/tex]
Hope it helps!
From ItsNobody