Answer:
[tex] z = \frac{1-1.37}{\frac{0.67}{\sqrt{13}}} = -1.991[/tex]
And we want this probability:
[tex] P(z<-1.991)[/tex]
And using the normal standard distribution or excel we got:
[tex] P(z<-1.991)= 0.0233[/tex]
And the best option would be:
D 0.0233
Step-by-step explanation:
For this case we have the following parameters:
[tex] \mu = 1.37, \sigma =0.67[/tex]
And we select a sample size of n=13. And we want to find this probability:
[tex] P(\bar X <1)[/tex]
We can assume that the distribution for this case is normal and then we can use the z score formula given by:
[tex] z= \frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n}}}[/tex]
And if we replace the data given we got:
[tex] z = \frac{1-1.37}{\frac{0.67}{\sqrt{13}}} = -1.991[/tex]
And we want this probability:
[tex] P(z<-1.991)[/tex]
And using the normal standard distribution or excel we got:
[tex] P(z<-1.991)= 0.0233[/tex]
And the best option would be:
D 0.0233