Respuesta :
Answer:
For this case is the rectangle is dilated a factor of 2.2 we assume that the expansion is in all the dimensions so then the new length and width are:
[tex] L_f = 2.2 L_i= 2.2* 7.5 in = 16.5 in[/tex]
[tex] W_f = 2.2 w_i = 2.2 * 3 in = 6.6 in[/tex]
Step-by-step explanation:
The area of a rectangle is given by [tex] A = L *W[/tex]
For this case is the rectangle is dilated a factor of 2.2 we assume that the expansion is in all the dimensions so then the new length and width are:
[tex] L_f = 2.2 L_i= 2.2* 7.5 in = 16.5 in[/tex]
[tex] W_f = 2.2 w_i = 2.2 * 3 in = 6.6 in[/tex]
And the area would be (2.2)^2 times the initial area since is defined as [tex]A = L_f W_f [/tex]
Answer:
The length and the width of the new rectangle are 16.5 inches and 6.6 inches respectively
Step-by-step explanation:
Given
Shape: Rectangle
[tex]Length = 7.5 inches[/tex]
[tex]Width = 3 inches[/tex]
[tex]Scale factor = 2.2[/tex]
Required
Dimension of the new rectangle
The dimensions of the new rectangle can be solved by multiplying the scale factor by the old dimensions;
This means that
New Length = Scale factor * Old Length
and
New Width = Scale factor * Old Width
Calculating the new length
New Length = Scale factor * Old Length
Substitute 2.2 for scale factor and 7.5 for old length; This gives
[tex]New Length = 2.2 * 7.5 inches[/tex]
[tex]New Length = 16.5 inches[/tex]
Calculating the new width
New Width = Scale factor * Old Width
Substitute 2.2 for scale factor and 3 for old width; This gives
[tex]New Width = 2.2 * 3 inches[/tex]
[tex]New Width= 6.6 inches[/tex]
Hence, the length and the width of the new rectangle are 16.5 inches and 6.6 inches respectively