Question

The equation y minus two-thirds = negative 2 (x minus one-fourth) is written in point-slope form. What is the equation in slope-intercept form? Y = negative 2 x minus StartFraction 1 Over 6 EndFraction y = negative 2 x + StartFraction 7 Over 6 EndFraction y = negative 2 x + StartFraction 5 Over 12 EndFraction y = negative 2 x minus StartFraction 11 Over 12 EndFraction

Answer 1

Answer:

(B)  $y=-2x+ \dfrac{7}{6}$

Step-by-step explanation:

Given the point-slope form of the equation of a line below:

$y-\dfrac{2}{3}=-2\left(x- \dfrac{1}{4}\right)$

We are required to write it in the slope-intercept form, y=mx+c.

$y-\dfrac{2}{3}=-2\left(x- \dfrac{1}{4}\right)\\\\y-\dfrac{2}{3}=-2x+ \dfrac{2}{4}\\\\y=-2x+ \dfrac{2}{4}+\dfrac{2}{3}\\\\y=-2x+ \dfrac{7}{6}$

The slope intercept form is:

$y=-2x+ \dfrac{7}{6}$

The correct option is B.

Answer 2

Answer:

b

Step-by-step explanation: