Answer:
Perimeter and area of drawing
Perimeter= 10 In
Area = 6.25 In²
Perimeter and area of object
Perimeter = 51.836 mm
Area = 167.936 mm²
Step-by-step explanation:
We are dealing with a square object, so let's talk about the drawing first.
The length of one side = 2.5 In
Perimeter of square= 4L
Perimeter = 4*2.5
Perimeter= 10 In
Area = L*L
Area = 2.5*2.5
Area = 6.25 In²
Letd note that 1 inch =
25.4 millimetres
So 2.5 Inch = 2.5 * 25.4
2.5 In = 63.5 mm.
25.4 mm is to 5mm
63.5 mm is to (63.5*5)/24.5
63.5mm is to 12.959 mm
So the length of actual object is 12.959mm
The perimeter = 4*12.959
Perimeter = 51.836 mm
Area = 12.959²
Area = 167.936 mm²
Answer:
The perimeter of the actual object is 50 mm.
The area of the actual object is 156.25 mm square
Step-by-step explanation:
Given
Shape: Square
Scale: 1 in : 5 mm
Length of Scale Drawing = 2.5 in
Required:
- Perimeter of Actual Object
- Area of Actual Object
Calculating the perimeter of the actual object
Provided that the shape is a square;
The perimeter of the actual object is calculated by
Perimeter = 4 * Length
Recall that the scale is 1 in : 5 mm
This means 1 in on the scale represents 5 mm of the actual measurements of the object.
So, if 1 in ≈ 5 mm, then
2.5 in ≈ 2.5 * 5 mm
2.5 in = 12.5 mm
So, Length = 12.5mm
Now, the perimeter of the actual object can be calculated.
P = 4 * 12.5mm
P = 50mm
Hence, the perimeter of the actual measurements is 50 mm.
Calculating the area of the actual object
The area of the actual object is calculated by
Area = Length * Length
Recall that Length = 12.5 mm as calculated above
So,
Area = 12.5 * 12.5
Area = 156.25 mm square
Hence, the area of the actual object is 156.25 mm square
