Question

What's the tenth term of a sequence with an explicit rule of ƒ(n) = 2 + (–3)(n – 1)?

Answer 1

Answer:

$-25$

Step-by-step explanation:

Given: $f(n)=2+(-3)(n-1)$

To find: tenth term of a sequence

Solution:

A sequence is a list of numbers in which order does matter and repetitions are allowed. A term is a number in the sequence.

For example in the sequence 1, 3, 5, 7, 9, ....,3 is the second term,9 is the fifth term.

To find the tenth term of a sequence, put n = 10 in $f(n)=2+(-3)(n-1)$

$f(n)=2+(-3)(n-1)\\=2+(-3)(10-1)\\=2+-3(9)\\=2-27\\=-25$