We have been given that [tex]\text{sin}(A)=\frac{12}{13}[/tex] and angle A is in quadrant 1. We are asked to find the exact value of [tex]\text{cot}(A)[/tex] in simplest radical form.
We know that sine relates opposite side of right triangle with hypotenuse.
[tex]\text{sin}=\frac{\text{Opposite}}{\text{Hypotenuse}}[/tex]
This means that opposite side is 12 units and hypotenuse is 13 units.
We know that cotangent relates adjacent side of right triangle with adjacent side.
[tex]\text{cot}=\frac{\text{Adjacent}}{\text{Opposite}}[/tex]
Now we will find adjacent side using Pythagoras theorem as:
[tex]\text{Adjacent}^2=\text{Hypotenuse}^2-\text{Oppoiste}^2[/tex]
[tex]\text{Adjacent}^2=13^2-12^2[/tex]
[tex]\text{Adjacent}^2=169-144[/tex]
[tex]\text{Adjacent}^2=25[/tex]
Let us take positive square root on both sides:
[tex]\sqrt{\text{Adjacent}^2}=\sqrt{25}[/tex]
[tex]\text{Adjacent}=5[/tex]
Therefore, adjacent side of angle A is 5 units.
[tex]\text{cot}(A)=\frac{5}{12}[/tex]
Therefore, the exact value of cot A is [tex]\frac{5}{12}[/tex].