Answer:
- no real solutions
- 2 complex solutions
Step-by-step explanation:
The equation can be rearranged to vertex form:
x^2 -4x = -5 . . . . . . . . . subtract 4x
x^2 -4x +4 = -5 +4 . . . . add 4
(x -2)^2 = -1 . . . . . . . . . show the left side as a square
x -2 = ±√-1 = ±i . . . . . . take the square root; the right side is imaginary
x = 2 ± i . . . . . . . . . . . . . add 2. These are the complex solutions.
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Comment on the question
Every 2nd degree polynomial equation has two solutions. They may be real, complex, or (real and) identical. That is, there may be 0, 1, or 2 real solutions. This equation has 0 real solutions, because they are both complex.
