Question

The graph shows the function g(x) for a restricted domain.

On a coordinate plane, a function starts at (negative 4, 0) and then curves through the y-axis at (0, 1.5) and then goes through point (4, 2).

Which is the function g(x) for a restricted domain?

g(x) = Negative RootIndex 3 StartRoot x minus 4 EndRoot; x greater-than-or-equal-to –4
g(x) = Negative RootIndex 3 StartRoot x 4 EndRoot + 4; x greater-than-or-equal-to 0
g(x) = Negative RootIndex 3 StartRoot x + 4 EndRoot; x greater-than-or-equal-to –4
g(x) = Negative RootIndex 3 StartRoot x EndRoot minus 4; x greater-than-or-equal-to 0

Answer 1

Answer:

f(-3)=g(-3)

Step-by-step explanation:

The graph shows two linear functions that intersect at (-3,-4).

The blue line is f(x).

At the point of intersection:

....eqn1

The blue line is g(x).

At the point of intersection

....eqn2

Equating both equations we get:

The statement that is true regarding the two functions is that:

HOPE THIs HELPS

Answer 2

Answer:

Option 3

g(x) = Negative RootIndex 3 StartRoot x + 4 EndRoot; x greater-than-or-equal-to –4

Step-by-step explanation:

Since the graph starts at x = -4 and towards the right, domain is x 》-4

g(x) = -(x + 4)^⅓

Because,

0 = -(-4 + 4)^⅓

0 = 0