Question

consider a silver wire with a radius of 4.0 x 10^-3 meter. determine the cross sectional area of this wire

Answer 1

Answer:

5.024×10⁻⁵ m

Explanation:

A = πr²................ Equation 1

Where A = cross sectional area of the wire, r = radius of the wire, π = pie.

Given: r = 4.0×10⁻³ meter.

Constant: π = 3.14.

Substitute these values into equation 1

A = 3.14(4.0×10⁻³)²

A = 3.14×16×10⁻⁶

A = 50.24×10⁻⁶

A = 5.024×10⁻⁵ m.

Hence the cross sectional area of the wire = 5.024×10⁻⁵ m

Answer 2

The cross sectional area of this wire will be "5.024 × 10⁻⁵ m". To understand the calculation, check below.

Cross-sectional area

According to the question,

Radius of silver wire, r = 4.0 × 10⁻³ m

Constant, π = 3.14

We know the formula,

→ Area will be:

A = πr²

By substituting the above values,

  = 3.14 × (4.0 × 10⁻³)²

  = 3.14 × 16 × 10⁻⁶

  = 5.024 × 10⁻⁵ m

Thus the above answer is right.

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