Question

The specific heat of a liquid x is 2.09 cal/g°c. A sample amount of grams of this liquid at 101 k is heated to 225 k. the liquid absorbs 5.23 kcals. what is the sample of liquid in grams? (round off decimal in the answer to nearest tenths)

Answer 1

Answer: 20 grams

Explanation:

The quantity of heat required to raise the temperature of a substance by one degree Celsius is called the specific heat capacity.

$Q=m\times c\times \Delta T$

Q = Heat absorbed by liquid = 5.23 kcal = 5230 cal    (1kcal=1000cal)

C = heat capacity of liquid = $2.09cal/g^0C$

Initial temperature of the liquid  = $T_i$ = 101 K

Final temperature of the liquid  = $T_f$  = 225 K

Change in temperature ,$\Delta T=T_f-T_i=(225-101)K=124K$

Putting in the values, we get:

$5230=m\times 2.09cal/g^0C\times 124K$

$m=20g$

Thus the sample of liquid in grams is 20